5v^2=500

Solution for 5v^2=500 equation:

5v^2=500

We move all terms to the left:

5v^2-(500)=0

a = 5; b = 0; c = -500;
Δ = b2-4ac
Δ = 02-4·5·(-500)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100}{2*5}=\frac{-100}{10}
=-10
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100}{2*5}=\frac{100}{10}
=10
$